Q. Whenever a hydrogen atom emits a photon in the Balmer series:

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A

It may emit another photon in the Balmer series

B

It must emit another photon in the Lyman series

C

The second photon, if emitted, will have a wavelength of about 122 nm

D

It may emit a second photon, but the wavelength of this photon cannot be predicted

Solution:

Whenever a photon is emitted in Balmer series, it will be corresponding to the transition of electron to $n=2$ state from where it will further transit to ground state and emit a line corresponding to the transition of $n=2$ to $n=1$ in Lyman series of which the wavelength can be given as $\lambda=12431 / 10,2\, eV\approx 122\, nm$

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