Q. Two smooth blocks are placed at a smooth corner as shown in figure. Both the blocks are having mass $m$. We apply a force $F$ on the small block $m$. Block $A$ presses block $B$ in the normal direction, due to which pressing force on vertical wall will increase, and pressing force on the horizontal wall decreases, as we increases $F\left(\theta=37^{\circ}\right.$ with horizontal).
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As soon as the pressing force on the horizontal wall by block $B$ becomes zero, it will lose contact with ground. If the value of $F$ further increases, block $B$ will accelerate in the upward direction and simultaneously block $A$ will move towards right.
If the acceleration of block $A$ is $a$ rightwards, then the acceleration of block $B$ will be

Laws of Motion Report Error

Solution:

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To keep regular contact
$a \sin \theta=b \cos \theta$
$b=a \tan \theta=\frac{3}{4} a$