Q. The resistance of each arm of a wheatstone's bridge is $25\, \Omega$. A resistance of $25\, \Omega$ is connected in series with the galvanometer of resistance $50\, \Omega$. The equivalent resistance appearing across the battery is

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A

$25\, \Omega$

B

$100\, \Omega$

C

$2.5\, \Omega$

D

$20\, \Omega$

Solution:

Here we have all the four arms have the same resistance that is the given network is a balanced wheatstone's bridge. So no current flows through galvanometer. Therefore the effective resistance across the battery is given by $50 / 2=25$

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