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  4. The resistance of each arm of a wheatstone's bridge is 25 Ω. A resistance of 25 Ω is connected in series with the galvanometer of resistance 50 Ω. The equivalent resistance appearing across the battery is

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Q. The resistance of each arm of a wheatstone's bridge is $25\, \Omega$. A resistance of $25\, \Omega$ is connected in series with the galvanometer of resistance $50\, \Omega$. The equivalent resistance appearing across the battery is

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Solution:

Here we have all the four arms have the same resistance that is the given network is a balanced wheatstone's bridge. So no current flows through galvanometer. Therefore the effective resistance across the battery is given by $50 / 2=25$