Q. The escape velocity of a body projected vertically upwards from the earth’s surface is $11.2\, km/sec$. If the body is projected in a direction making $30^°$ angle to the vertical, its escape velocity in this case will be

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A

$11.2\, km/s$

B

$11.2 \times \left(1/2\right)\, km/s$

C

$11.2 \left(√3/2\right)\, km/s$

D

$11.2 \times \left(1/3\right)\, km/s$

Solution:

Escape velocity of a body $v_{e}=\sqrt{\frac{2GM_{e}}{R_{e}}}$
Escape velocity of a body is independent upon the angle of projection

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