1. Tardigrade
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  3. Physics
  4. The escape velocity of a body projected vertically upwards from the earth’s surface is 11.2 km/sec. If the body is projected in a direction making 30° angle to the vertical, its escape velocity in this case will be

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Q. The escape velocity of a body projected vertically upwards from the earth’s surface is $11.2\, km/sec$. If the body is projected in a direction making $30^°$ angle to the vertical, its escape velocity in this case will be

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Solution:

Escape velocity of a body $v_{e}=\sqrt{\frac{2GM_{e}}{R_{e}}}$
Escape velocity of a body is independent upon the angle of projection