Q. Paragraph 2
An amino acid reacts with $10\, ml 0.05\, M\, NaOH$ and the final solution has $pH =2.30$. When $20\, ml$ of the same base is added in the resulting solution, the $pH$ becomes $9.7$. Identify the amino acid and calculate the isoelectric point of the amino acid. This amino acid is prepared by the reaction of compound (X) with $NH _{3}$ and further hydrolysis with $HCN$. Compound (X) is less $C$ atom containing compound that gives positive iodoform test and positive Fehling's solution test.
Isoelectric point of the amino acid is:

Solution:

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When partial neutralisation of alanine occurs,
Then, $pH = p K_{ a }+\log \left[\frac{\text { salt }}{\text { acid }}\right]$
[salt]=[acid]
$pH _{1}= p _{ a 1}$ and $pH _{2}= p _{ a 2}$
$\therefore pH =\frac{ p _{ a _{1}}+ p _{ a _{2}}}{2}$
$=\frac{9.7+2.3}{2}=\frac{12.0}{2}=6.0$