Q. If in the first orbit of a hydrogen atom the total energy of the electron is $-21.76 \times 10^{-19} J$, then its electric potential energy will be:

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A

$-43.52 \times 10^{-19} J$

58%

B

$-21.76 \times 10^{-19} J$

20%

C

$-10.88 \times 10^{-19} J$

17%

D

$-13.6 \times 10^{-19} J$

5%

Solution:

Potential energy $=2$ Total energy
$\Rightarrow =2 \times-21.76 \times 10^{-19}$
$\Rightarrow =-43.52 \times 10^{-19} J .$

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