Q. An insecticide contains $47.5 \% C , 2.54 \% H$ and $50 \% Cl$ by mass. Its empirical formula is

Solution:

$C : H : Cl \,\,\,\,47.5 / 12: 2.54 / 1: 50 / 35.5$
$ 3.96 / 1.41: 2.54 / 1.41: 1.41 / 1.41$
$ 2.8: 1.8: 1$
$= C _{14} H _{9} Cl _{5}$