Q. The weight of a person is $60\, kg$. If he gets $10^{5}$ calories of heat through food and the efficiency of his body is $28 \%$, then upto how much height he can climb ? Take $g=10\, m s ^{-2}$ :

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A

100 m

B

196 m

C

400 m

D

1000 m

Solution:

Energy given to person
$=10^{5} cal$
$=418580\, J$
Energy that can be utilized $=418580 \times \frac{28}{100}$
$E=117202.4\, J$
$E =m g h$
$117202.4 =60 \times 10 \times h$
$h =195.34\, m \approx 196\, m$

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