Q. The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is $2\, kg$. Work done by all the forces acting on the particle in time interval between $t=0$ to $t=10\, s$ isPhysics Question Image

Work, Energy and Power Report Error

Solution:

From work-energy theorem,
$W =\Delta KE =K_{f}-K_{i}=\frac{1}{2} m\left(v_{f}^{2}-v_{i}^{2}\right)$
$=\frac{1}{2} \times 2\left[(-20)^{2}-(10)^{2}\right]=300\, J$