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  4. The lower and upper fixed points of a faulty thermometer are 5° and 99° respectively. If the reading of the thermometer is 52°, the temperature on the Fahrenheit scale is :

Q. The lower and upper fixed points of a faulty thermometer are $5^{\circ}$ and $99^{\circ}$ respectively. If the reading of the thermometer is $52^{\circ}$, the temperature on the Fahrenheit scale is :

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Solution:

$\frac{\text { Reading of faulty thermomenter }-L F P}{U F P-L F P}=\frac{F-32}{180}$
$\frac{52-5}{99-5}=\frac{F-32}{180}$
$90=F-32$
$F=122^{\circ} F$

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