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  4. The coefficient of static friction, μ s , between block A of mass 2kg and the table as shown in the figure is 0.2 . The maximum mass value of block B so that the two blocks do not move is (The string and the pulley are assumed to be smooth and massless g=10ms- 2. <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-dp7ax3tj1jy5zr7c.jpg />

Q. The coefficient of static friction, $\mu _{s} ,$ between block $A$ of mass $2kg$ and the table as shown in the figure is $0.2$ . The maximum mass value of block $B$ so that the two blocks do not move is (The string and the pulley are assumed to be smooth and massless $g=10ms^{- 2}\left.$
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Solution:

Condition for not moving the block is that the tension in the string should be equal to static frictional force, here tension will be equal to $m_{B}g$
$ \, \, m_{B} \, g=\mu _{s} \, m_{A} \, g \\ \Rightarrow \, m_{B}=\mu _{s} \, m_{A} \\ or, \, \, \, m_{B}=0.2\times 2=0.4 \, kg$

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