Q. The binding energy per nucleon for ${ }_{1} H^{2}$ and ${ }_{2} He ^{4}$ are $1.1 \,M \,eV$ and $7.0 \,M\,eV$ respectively. The energy released when two ${ }_{1} H ^{2}$ fuse to form ${ }_{2} He ^{4}$ is

Solution:

$Q=(7 \times 4)-(2 \times 2 \times 1.1)=23.6\, M\,eV$