Q. Logarithms of readings of pressure and volume for an ideal gas were plotted on a graph as shown in figure-3.86. By measuring the gradient, it can be shown that the gas may be :

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Solution:

As the graph of logarithm of and is a straight line the process must be adiabatic as the process equation will be constant or so the negative of slope of the curve gives the value of which is for a diatomic gas.

Questions from Thermodynamics