Q. In the circuit shown in figure-, the potential difference across the capacitor is . Each resistance is of . The cell is ideal. The EMF of the cell is :

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Solution:

In the circuit shown in figure if a current is supplied by the battery then it is divided in resistances and in parallel as shown.

In steady state no current will flow through the branch of capacitor so equivalent resistance across the battery is given as

Thus current through battery is given as

In above circuit writing KVL equation from terminal to of capacitor gives


Substituting value of current in above equation, we get