Q. In the circuit diagram, the current through the battery immediately after the switch $S$ is closed is given as :

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A

Zero

B

$\frac{E}{R_{1}}$

C

$\frac{E}{R_{1}+R_{2}}$

D

$\frac{E}{R_{1}+\frac{R_{2} R_{3}}{R_{2}+R_{3}}}$

Solution:

Just after the switch is closed $C_{1}$ is short circuited and current passes through $R_{1}$ and $C_{1}$ only so it is given as $E / R_{1}$.

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