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  4. If the stationary proton and α - particle are accelerated through same potential difference, the ratio of de Broglie's wavelength will be

Q. If the stationary proton and - particle are accelerated through same potential difference, the ratio of de Broglie's wavelength will be

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Solution:

The gain in K.E. of a charged particle after moving through a potential difference of is given by , that is also equal to where is the velocity of the charged particle. Disregarding the relativistic effect,



de Broglie wavelength

Putting

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