Q. Given that $Y=a \sin \omega t+ bt +ct^{2} \cos \omega t$. The unit of $a b c$ is same as that of
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Solution:
$y=a \sin \omega t+b t+c t^{2} \cos \omega t$
Here $a=y ; b=y / t ; c=y / t^{2}$
$\therefore a \times b \times c=y \times y / t \times y / t^{2}=(y / t)^{3}$
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