Q. For what value of $R$ in the circuit as shown current passing through $4 \Omega $ resistance will be zero

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A

$1 \Omega $

B

$2 Ω$

C

$3 Ω$

D

$4 Ω$

Solution:

When the current through $4 \Omega $ resistance is zero, then $V_{A}-V_{B}=6V$

i.e., the potential difference across $2\Omega$ resistance would be $10-6=4V$
$\therefore $ Current through $2\Omega$ resistance is $2A$ .
The potential difference across R is $\left(6 - 4\right)V$ and $2A$ flows through it
$\overset{}{\Rightarrow } \, R \, =\frac{6 - 4}{2}$
$\therefore R=1\Omega$

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