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  4. For adiabatic expansion of a monoatomic perfect gas, the volume increases by 2.4 %. What is the percentage decrease in pressure ?

Q. For adiabatic expansion of a monoatomic perfect gas, the volume increases by $2.4\%$. What is the percentage decrease in pressure ?

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Solution:

For a monoatomic gas,
$\gamma =1.6$
$P V^{\gamma} =$ constant
$P V =P^{\prime}\left(V+\frac{2.4}{100} V\right)^{\gamma}$
$P^{\prime} =0.96 P$
Percentage decrease in pressure
$=\frac{P-0.96 P}{P} \times 100$
$=4 \%$

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