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An ideal cell of emf 10 V is connected in circuit shown in figure. Each resistance is 2 Ω. The potential difference (in V ) across the capacitor when it is fully charged is <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/8ba47ce13a1d04ce2244a859a13c413e-.png />

Q. An ideal cell of emf $10\, V$ is connected in circuit shown in figure. Each resistance is $2\, \Omega$. The potential difference (in $V$ ) across the capacitor when it is fully charged is_____

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Solution:

$R _{1}$ to $R _{5} \rightarrow$ each $2 \Omega$
$•$Cap. is fully charged
$•$So no current is there in branch $A D B$
$•$Effective circuit of c urrent flow :

$R _{ eq }=\left(\frac{4 \times 2}{4+2}\right)+2$
$R _{ eq }=\frac{4}{3}+2=\frac{10}{3} \Omega $
$i =\frac{10}{10 / 3}=3 A$
So potential different across $ AEB $
$\Rightarrow 2 \times 1+2 \times 3=8 V$
Hence potential difference across
Capacitor $=\Delta V = V _{ AEB }=8 V$

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