Q. An ammeter reads up to $1$ ampere. Its internal resistance is $0.81\, ohm$. To increase the range to $10\, A$ the value of the required shunt ( in ohm) is

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A

$0.3$

B

$0.9$

C

$0.09$

D

$0.03$

Solution:

shunt resistance required is given by
$S = I _{ g } G / l I _{ g }$.
here, $I _{ g }=1 A , G =0.81 \,ohm$
and $I =10 A$ Substituting we get
$S=1 \times 0.81 / 10-1=0.81 / 9=0.090\, h\, hm$

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