Q. An A.C. source of voltage $\text{V} = 100 \, sin \left(\right. 100 \, \text{\pi t} \left.\right)$ is connected to a resistor of resistance $20 \, \, \Omega $ . The rms value of current through resistor is
Solution:
$\text{I}_{0} = \frac{\text{V}_{0}}{\text{R}} = \frac{\text{100}}{\text{20}} = \text{5 A}$
$\therefore \text{I}_{\text{rms}} = \frac{\text{I}_{0}}{\sqrt{2}} = \frac{5}{\sqrt{2}} \text{ A}$
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