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- A small ball B of mass m is suspended with light inelastic string of length L from a block A of same mass m which can move on smooth horizontal surface as shown in the figure. The ball is displaced by angle θ from equilibrium position & then released. <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-4trft5wpz4fys7ro.jpg /> The displacement of block when ball reaches the equilibrium position is
Q.
A small ball B of mass m is suspended with light inelastic string of length L from a block A of same mass m which can move on smooth horizontal surface as shown in the figure. The ball is displaced by angle $\theta $ from equilibrium position & then released.
The displacement of block when ball reaches the equilibrium position is
Solution:
$Δ \text{x}_{\text{cm}} = 0$
$0 = - \left(\text{L sin} \theta - \text{x}\right) \text{m} + \text{mx}$
$\text{L sin} \theta - \text{x} = \text{x}$
$2 \text{x} = \text{L sin} \theta $
$\text{x} = \left(\text{L sin} \theta \right) / 2$

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