Q. A ring of mass m and radius R has three particle attached to the ring as shown in the figure. The centre of the ring has a speed v0. The kinetic energy of the system is (slipping is absent).
Question

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Solution:

$\text{KE} = \frac{1}{2} \text{m} \left(\text{v}_{0}^{2}\right) + \frac{1}{2} \left(\text{mR}\right)^{2}\right) \left( \left(\frac{\left(\text{v}\right)_{0}}{\text{R}}\right)^{2}$
$= \frac{1}{2} \left(3 \text{m}\right) \left( \left(\sqrt{2} \left(\text{v}\right)_{0}\right)^{2} + \frac{1}{2} \left(\text{m}\right) \left( \left(2 \left(\text{v}\right)_{0}\right)^{2}$
$= 6 \text{m} \text{v}_{0}^{2}$