Q. A pendulum clock which ticks $60$ times in one minute on earth is placed on the moon where the acceleration due to gravity is only one-sixth of that on the earth. How many times the clock will tick over there in one minute?

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A

12.25

B

24.5

C

2.45

D

0.245

Solution:

$\left(\text{T}\right)^{′} = 2 \pi \sqrt{l / \left(\text{g} / 6\right)} = \sqrt{6} T$ Hence, the clock will tick in one minute
$= 6 0 / \sqrt{6} = 2 4 \text{.} 5$ times

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