Question

A gas is expanded from volume $V_{0}$ to $2 V_{0}$ under three different processes. Process $1$ is isobaric process, process $2$ is isothermal and process 3 is adiabatic. Let $\Delta U_{1}, \Delta U_{2}$ and $\Delta U_{3}$, be the change in internal energy of the gas is these processes. Then :

• A. $\Delta U_{1} > \Delta U_{2} > \Delta U_{3}$
• B. $\Delta U_{1} < \Delta U_{2} < \Delta U_{3}$
• C. $\Delta U_{2} < \Delta U_{1} < \Delta U_{3}$
• D. $\Delta U_{2} < \Delta U_{3} < \Delta U_{1}$

Answer 1

Answer: (A)

As $\Delta U_{1}=+ve; $
and $\Delta U_{2}=0$
So $\Delta U_{3}=$-ve
thus $\Delta U_{1} > \Delta U_{2} > \Delta U_{3}$