Question

A block of mass lies on a wedge of mass . The wedge in turn lies on a smooth horizontal surface. Friction is absent everywhere. The wedge-block system is released from rest. All situations given in Column I are to be estimated in duration the block undergoes a vertical displacement starting from rest. Match the statements in Column I with the results in Column II. ( is acceleration due to gravity.)

Column I		Column II
i	Work done by normal reaction acting on the block is	a	positive
ii	Work done by normal reaction (exerted by block) acting on the wedge is	b	negative
iii	The sum of work done by normal reaction on the block and work done by normal on wedge	c	zero
iv	Net work done by all forces on the block is	d	less than mgh in magnitude

• A. i a; ii b, c, d; iii b, c, d; iv c
• B. i a, c; ii b, c; iii c; iv b, d
• C. i a; ii b; iii b; iv b
• D. i b d; ii a, d; iii c, d; iv a, d

Answer 1

Answer: (D)

(i) Angle between velocity of the block and normal reaction on the block is obtuse. Hence, work done by normal reaction on the block is negative.

As the block falls by vertical distance , from work-energy theorem,
Work done by + work done by of the block
work done by

(ii) Work done by normal reaction on wedge is positive.
Since loss in PE of the block = of wedge of block, work done by normal reaction on the wedge of the wedge.
Therefore, work done by on the wedge is less than .
(iii) Net work done by normal reaction on the block and wedge is zero.
(iv) The net work done by all forces on the block is positive, because its kinetic energy has increased.
Also of the block is less than .
Hence, net work done on the block final of the block .