Zinc and hydrochloric acid react according to the following reaction: Zn (s)+2 HCl (a q .) arrow ZnCl 2(a q .)+ H 2(g) If 0.30 mole of Zn is added to 0.52 mole HCl, how many moles of H 2 are produced?

Question

Zinc and hydrochloric acid react according to the following reaction: Zn (s)+2 HCl (a q .) arrow ZnCl 2(a q .)+ H 2(g) If 0.30 mole of Zn is added to 0.52 mole HCl, how many moles of H 2 are produced? (A) 0.2 (B) 0.62 (C) 0.6 (D) 0.26

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-eaovk5u2uqi9m4bf.jpg" /> ∵ Mole ratio of Zn:HCl:H2 is 1:2:1 2 textmole HCl textgives=1 textmole textH text2 0.52 textmoleHCl textgives=(1 × 0.52/2)=0.26 textmole Note that HCl is used completely and thus it is limiting reagent.

Q. Zinc and hydrochloric acid react according to the following reaction :
$Z n (s) + 2 H Cl (a q .) \to Z n C l_{2} (a q .) + H_{2} (g)$
If $0.30$ mole of $Z n$ is added to $0.52$ mole $H Cl$ , how many moles of $H_{2}$ are produced?

$0.2$

$0.62$

$0.6$

$0.26$

$∵$ Mole ratio of $Z n : H Cl : H_{2}$ is $1 : 2 : 1$
$2 mole H Cl gives = 1 mole H_{2}$
$0.52 mole H Cl gives = \frac{1 \times 0.52}{2} = 0.26 mole$
Note that $H Cl$ is used completely and thus it is limiting reagent.

Q. Zinc and hydrochloric acid react according to the following reaction : Zn(s)+2HCl(aq.)→ZnCl2​(aq.)+H2​(g) If 0.30 mole of Zn is added to 0.52 mole HCl, how many moles of H2​ are produced?

0.2

0.62

0.6

0.26