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  4. Zinc and hydrochloric acid react according to the following reaction: Zn (s)+2 HCl (a q .) arrow ZnCl 2(a q .)+ H 2(g) If 0.30 mole of Zn is added to 0.52 mole HCl, how many moles of H 2 are produced?

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Q. Zinc and hydrochloric acid react according to the following reaction :
$Zn (s)+2 HCl (a q .) \rightarrow ZnCl _2(a q .)+ H _2(g)$
If $0.30$ mole of $Zn$ is added to $0.52$ mole $HCl$, how many moles of $H _2$ are produced?

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$\because$ Mole ratio of $Zn:HCl:H_{2} \,$ is $\, 1:2:1$
$2 \, \, \text{mole} \, \, HCl \, \, \text{gives}=1 \, \, \text{mole} \, \text{H}_{\text{2}}$
$0.52 \, \, \text{mole}HCl \, \, \text{gives}=\frac{1 \times 0.52}{2}=0.26 \, \, \text{mole}$
Note that $HCl$ is used completely and thus it is limiting reagent.