Question

$Xe{O}_4$ molecule is tetrahedral having '$x$' number of $p\pi -d\pi$ bonds. The value of $x$ is.

Answer 1

Answer: 4

Xenon atom in $Xe{O}_4$ undergo $s{p}^3$ hybridization.

In the fourth excited state, xenon atom has $8$ unpaired electrons

One s and three p orbitals undergo $s{p}^3$ hybridization. Four $s{p}^3$ hybrid orbitals form four $\sigma$ bonds with oxygen atoms. They are $\sigma s{p}^3-p$ bonds. Four $p\pi -d\pi$ bonds are also formed with oxygen atoms by the unpaired electrons in the $d$ orbitals of xenon.