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Q.
$XeO_{4}$ molecule is tetrahedral having '$x$' number of $p\pi -d\pi $ bonds. The value of $x$ is.
NTA AbhyasNTA Abhyas 2022
Solution:
Xenon atom in $XeO_4$ undergo $sp^3$ hybridization.
In the fourth excited state, xenon atom has $8$ unpaired electrons
One s and three p orbitals undergo $s p^{3}$ hybridization. Four $sp^{3}$ hybrid orbitals form four $\sigma $ bonds with oxygen atoms. They are $\sigma \, s p^{3} \, -p$ bonds. Four $p\pi -d\pi $ bonds are also formed with oxygen atoms by the unpaired electrons in the $d$ orbitals of xenon.
