Work for the following process A B C D on a monoatomic gas is :

Question

Work for the following process A B C D on a monoatomic gas is : (A) w =-2 P 0 V 0 ln 2 (B) w =-2 P 0 V 0 (1+ln 2) (C) w =- P 0 V 0 (1+ln 2) (D) w=-P0 V0 ln 2

Tardigrade Admin · Accepted Answer

At A and D the temperatures of the gas will be equal, so Δ E =0, Δ H =0 Now W = W AB + W BC + W CD =- P 0 V 0-2 P 0 V 0 ln 2+ P 0 V 0 =-2 P0 V0 ln 2

Q. Work for the following process $A BC D$ on a monoatomic gas is :

$w = - 2 P_{0} V_{0}$ ln 2

$w = - 2 P_{0} V_{0}$ (1+ln 2)

$w = - P_{0} V_{0}$ (1+ln 2)

$w = - P_{0} V_{0}$ ln 2

At $A$ and $D$ the temperatures of the gas will be equal, so

$Δ E = 0, Δ H = 0$

Now $W = W_{A B} + W_{BC} + W_{C D} = - P_{0} V_{0} - 2 P_{0} V_{0} ln 2 + P_{0} V_{0}$

$= - 2 P_{0} V_{0} ln 2$

Q. Work for the following process ABCD on a monoatomic gas is :

w=−2P0​V0​ ln 2

w=−2P0​V0​ (1+ln 2)

w=−P0​V0​ (1+ln 2)

w=−P0​V0​ ln 2