Question

Work for the following process $A B C D$ on a monoatomic gas is :

• A. $w =-2\, P _{0}\, V _{0} $ ln 2
• B. $w =-2\, P _{0} \,V _{0}$ (1+ln 2)
• C. $w =- P _{0}\, V _{0}$ (1+ln 2)
• D. $w=-P_{0} \,V_{0} $ ln 2

Answer 1

Answer: (A)

At $A$ and $D$ the temperatures of the gas will be equal, so

$\Delta E =0, \,\,\, \Delta H =0$

Now $W = W _{ AB }+ W _{ BC }+ W _{ CD }=- P _{0} V _{0}-2 P _{0} V _{0} \ln 2+ P _{0} V _{0}$

$=-2 P_{0} V_{0} \ln 2$