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Tardigrade
Question
Physics
Work done for the process shown in the figure is
Q. Work done for the process shown in the figure is
2954
228
Thermodynamics
Report Error
A
1 J
B
1.5 J
C
4.5 J
D
0.3 J
Solution:
Area under graph and
V
axis = work done
=
2
1
×
(
30
+
10
)
×
1
0
3
×
(
25
−
10
)
×
1
0
−
6
=
0.3
J