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  4. Work done for the process shown in the figure is

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Q. Work done for the process shown in the figure isPhysics Question Image

Thermodynamics

Solution:

image
Area under graph and $V$ axis = work done
$=\frac{1}{2} \times(30+10) \times 10^{3} \times(25-10) \times 10^{-6} $
$=0.3\, J$