Work done by air when it expands from 50 L 10 150 L at a constant pressure of 2 atmosphere is

Question

Work done by air when it expands from 50 L 10 150 L at a constant pressure of 2 atmosphere is (A)  2× 104J  (B)  2× 102J  (C)  2× 1011J  (D)  2× 1015J

Tardigrade Admin · Accepted Answer

According to formula W=P (V2-V1) Given: P=2× 105 N text/m2, V1=50× 10-3m3, V2=150× 10-3m3 ∴ W=2× 105(150-50)× 10-3 W=2× 105× 100× 10-3 W=2× 104J

Q. Work done by air when it expands from 50 L 10 150 L at a constant pressure of 2 atmosphere is

$2 \times 10^{4} J$

$2 \times 10^{2} J$

$2 \times 10^{11} J$

$2 \times 10^{15} J$

According to formula $W = P (V_{2} - V_{1})$ Given : $P = 2 \times 10^{5} N / m^{2},$ $V_{1} = 50 \times 10^{- 3} m^{3},$ $V_{2} = 150 \times 10^{- 3} m^{3}$ $∴$ $W = 2 \times 10^{5} (150 - 50) \times 10^{- 3}$ $W = 2 \times 10^{5} \times 100 \times 10^{- 3}$ $W = 2 \times 10^{4} J$

Q. Work done by air when it expands from 50 L 10 150 L at a constant pressure of 2 atmosphere is

2×104J

2×102J

2×1011J

2×1015J

According to formula W=P(V2​−V1​) Given : P=2×105N/m2, V1​=50×10−3m3, V2​=150×10−3m3 ∴ W=2×105(150−50)×10−3 W=2×105×100×10−3 W=2×104J

$2 \times 10^{4} J$

$2 \times 10^{2} J$

$2 \times 10^{11} J$

$2 \times 10^{15} J$

According to formula $W = P (V_{2} - V_{1})$ Given : $P = 2 \times 10^{5} N / m^{2},$ $V_{1} = 50 \times 10^{- 3} m^{3},$ $V_{2} = 150 \times 10^{- 3} m^{3}$ $∴$ $W = 2 \times 10^{5} (150 - 50) \times 10^{- 3}$ $W = 2 \times 10^{5} \times 100 \times 10^{- 3}$ $W = 2 \times 10^{4} J$