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Q. Work done by air when it expands from 50 L 10 150 L at a constant pressure of 2 atmosphere is

CMC MedicalCMC Medical 2007

Solution:

According to formula $ W=P\,({{V}_{2}}-{{V}_{1}}) $ Given : $ P=2\times {{10}^{5}}\,N\text{/}{{m}^{2}}, $ $ {{V}_{1}}=50\times {{10}^{-3}}{{m}^{3}}, $ $ {{V}_{2}}=150\times {{10}^{-3}}{{m}^{3}} $ $ \therefore $ $ W=2\times {{10}^{5}}(150-50)\times {{10}^{-3}} $ $ W=2\times {{10}^{5}}\times 100\times {{10}^{-3}} $ $ W=2\times {{10}^{4}}J $