Will the dissociation of PCl5 in the reaction PCl5(g)PCl3(g)+Cl2(g);Δ H=+2.22 Kcal be favoured by

Question

Will the dissociation of PCl5 in the reaction PCl5(g)PCl3(g)+Cl2(g);Δ H=+2.22 Kcal be favoured by (A) increasing temperature (B) increasing pressure (C) adding more PCl3  (D) adding more Cl2

Tardigrade Admin · Accepted Answer

: As the reaction is endothermic and accompanied by an increase in volume, according to Le Chateliers principle favourable conditions for dissociation of PCl5 is increase in temperature and decrease in pressure.

Q. Will the dissociation of $PC l_{5}$ in the reaction $PC l_{5} (g) PC l_{3} (g) + C l_{2} (g); Δ H = + 2.22$ Kcal be favoured by

increasing temperature

increasing pressure

adding more $PC l_{3}$

adding more $C l_{2}$

: As the reaction is endothermic and accompanied by an increase in volume, according to Le Chateliers principle favourable conditions for dissociation of $PC l_{5}$ is increase in temperature and decrease in pressure.

Q. Will the dissociation of PCl5​ in the reaction PCl5​(g)PCl3​(g)+Cl2​(g);ΔH=+2.22 Kcal be favoured by

increasing temperature

increasing pressure

adding more PCl3​

adding more Cl2​

: As the reaction is endothermic and accompanied by an increase in volume, according to Le Chateliers principle favourable conditions for dissociation of PCl5​ is increase in temperature and decrease in pressure.

Q. Will the dissociation of $PC l_{5}$ in the reaction $PC l_{5} (g) PC l_{3} (g) + C l_{2} (g); Δ H = + 2.22$ Kcal be favoured by

adding more $PC l_{3}$

adding more $C l_{2}$

: As the reaction is endothermic and accompanied by an increase in volume, according to Le Chateliers principle favourable conditions for dissociation of $PC l_{5}$ is increase in temperature and decrease in pressure.