While performing a thermodynamics experiment, a student made the following observations, HCl + NaOH arrow NaCl + H 2 O Δ H =-57.3 kJ mol -1 CH 3 COOH + NaOH arrow CH3COONa + H 2 O Δ H =-55.3 kJ mol -1 . The enthalpy of ionization of CH 3 COOH as calculated by the student is kJ mol -1. (nearest integer)

Question

While performing a thermodynamics experiment, a student made the following observations, HCl + NaOH arrow NaCl + H 2 O Δ H =-57.3 kJ mol -1 CH 3 COOH + NaOH arrow CH3COONa + H 2 O Δ H =-55.3 kJ mol -1 . The enthalpy of ionization of CH 3 COOH as calculated by the student is kJ mol -1. (nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ H text ionisation text of CH 3 COOH =|-57.3-(-55.3)| =2 KJ / mol

ΔHionisation ​ of CH3​COOH=∣−57.3−(−55.3)∣ =2KJ/mol

$Δ H_{ionisation} of C H_{3} COO H = ∣ - 57.3 - (- 55.3) ∣$
$= 2 K J / m o l$