1. Tardigrade
  2. Question
  3. Chemistry
  4. While performing a thermodynamics experiment, a student made the following observations, HCl + NaOH arrow NaCl + H 2 O Δ H =-57.3 kJ mol -1 CH 3 COOH + NaOH arrow CH3COONa + H 2 O Δ H =-55.3 kJ mol -1 . The enthalpy of ionization of CH 3 COOH as calculated by the student is kJ mol -1. (nearest integer)

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Q. While performing a thermodynamics experiment, a student made the following observations,
$ HCl + NaOH \rightarrow NaCl + H _2 O$
$ \Delta H =-57.3 \,kJ \,mol ^{-1}$
$ CH _3 COOH + NaOH \rightarrow CH_3COONa + H _2 O$
$ \Delta H =-55.3 \,kJ\, mol ^{-1} .$
The enthalpy of ionization of $CH _3 COOH$ as calculated by the student is _____ $kJ \,mol ^{-1}$. (nearest integer)

JEE MainJEE Main 2022Thermodynamics

Solution:

$ \Delta H _{\text {ionisation }} \text { of } CH _3 COOH =|-57.3-(-55.3)| $
$ =2 \,KJ / mol $