Question

Which represents correct Nernst equation for redox reaction $O+n{e}^{-}\rightleftharpoons R$?

• A. $E=E^{\circ }-\frac{RT}{nF}$ In $\frac{\left[O\right]}{\left[R\right]}$
• B. $\frac{\left[O\right]}{\left[R\right]}=e^{\frac{nF}{RT}\left(E-E^{\circ }\right)}$
• C. $\frac{\left[O\right]}{\left[R\right]}=e^{\frac{-nF}{RT}\left(E-E^{\circ }\right)}$
• D. $\frac{\left[O\right]}{\left[R\right]}=e^{\frac{RT}{nF}\left(E-E^{\circ }\right)}$

Answer 1

Answer: (B)

$O+n{e}^{-}\rightleftharpoons R$
$E=E^{\circ }-\frac{RT}{nF}$ In $\frac{\left[R\right]}{\left[O\right]}$ - In $\frac{\left[R\right]}{\left[O\right]}=\frac{nF}{RT}\left(E-E^{\circ }\right)$
$\Rightarrow$ In $\frac{\left[O\right]}{\left[R\right]}$
$=\frac{nF}{RT}\left(E-E^{\circ }\right)$
So, $\frac{\left[O\right]}{\left[R\right]}=e^{\frac{nF}{RT}\left(E-E^{\circ }\right)}$