Question

Which represents correct Nernst equation for redox reaction $O + ne^{-} \rightleftharpoons R$?

• A. $E =E^{\circ} -\frac{RT}{nF}$ In $\frac{\left[O\right]}{\left[R\right]}$
• B. $ \frac{\left[O\right]}{\left[R\right]} =e^{\frac{nF}{RT}\left(E -E^{\circ}\right)}$
• C. $ \frac{\left[O\right]}{\left[R\right]} =e^{\frac{-nF}{RT}\left(E -E^{\circ}\right)}$
• D. $ \frac{\left[O\right]}{\left[R\right]} =e^{\frac{RT}{nF}\left(E -E^{\circ}\right)}$

Answer 1

Answer: (B)

$O + ne^{-} \rightleftharpoons R$
$E = E^{\circ} - \frac{RT}{nF}$ In $\frac{\left[R\right]}{\left[O\right]}$ - In $\frac{\left[R\right]}{\left[O\right]} = \frac{nF}{RT}\left(E - E^{\circ}\right)$
$\Rightarrow $ In $\frac{\left[O\right]}{\left[R\right]}$
$ = \frac{nF}{RT}\left(E - E^{\circ}\right)$
So, $\frac{\left[O\right]}{\left[R\right]} = e^{\frac{nF}{RT}\left(E - E^{\circ}\right)}$