Question

Which of the following will not have a mass of 10 g?

• A. $0.1molCaC{O}_3$
• B. $1.51\times 10^{23}C{a}^{2+}$ ions
• C. 0.16 mol of $C{O}_3$ ions
• D. $7.525\times 10^{22}$ Br atom

Answer 1

Answer: (C)

$0.1$ mole $CaC{O}_3=0.1\times 100=10g$
$1.51\times 10^{23}C{a}^{2+}$ ions $=\frac{1.51\times 10^{23}}{6.023\times 10^{23}}\times 40$
$0.16$ mol of $C{O}_3^{2-}$ ions $=0.16\times 60=9.6g$
$7.525\times 10^{22}Br$ atoms $=\frac{7.525\times 10^{22}}{6.02\times 10^{23}}\times 80$
$=10g$