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Q. Which of the following will not have a mass of 10 g?

Some Basic Concepts of Chemistry

Solution:

$0.1$ mole $CaCO_{3}=0.1\times100=10\,g$
$1.51\times10^{23}\, Ca^{2+}$ ions $=\frac{1.51\times10^{23}}{6.023\times10^{23}}\times40$
$0.16$ mol of $CO_{3}^{2-}$ ions $=0.16\times60=9.6\,g$
$7.525\times 10^{22}\,Br$ atoms $=\frac{7.525\times10^{22}}{6.02\times10^{23}}\times80$
$=10\,g$