Which of the following relation is correct :-

Question

Which of the following relation is correct :- (A) r=(a/2 √2) (body centred cubic) (B) r=(a √3/4) (face centred cubic) (C) (rNa+/rCl-)=0.225[In NaCl] (D) None

Tardigrade Admin · Accepted Answer

For BCCa√3=4r r=(a √3/4) For Fcc a√3=4r r=(a √3/4) For NaCl type solid r++r-=(a/2)

Q. Which of the following relation is correct :-

$r = \frac{a}{2 2}$ (body centred cubic)

$r = \frac{a 3}{4}$ (face centred cubic)

$\frac{r _{N a^{+}}}{r _{C l^{-}}} = 0.225 [I n N a Cl]$

None

For $BCC a 3 = 4 r$
$r = \frac{a 3}{4}$
For Fcc
$a 3 = 4 r$
$r = \frac{a 3}{4}$
For $N a Cl$ type solid
$r_{+} + r^{-} = \frac{a}{2}$

Q. Which of the following relation is correct :-

r=22​a​ (body centred cubic)

r=4a3​​ (face centred cubic)

rCl−​rNa+​​=0.225[InNaCl]

None

For BCCa3​=4r r=4a3​​ For Fcc a3​=4r r=4a3​​ For NaCl type solid r+​+r−=2a​

$r = \frac{a}{2 2}$ (body centred cubic)

$r = \frac{a 3}{4}$ (face centred cubic)

$\frac{r _{N a^{+}}}{r _{C l^{-}}} = 0.225 [I n N a Cl]$

For $BCC a 3 = 4 r$
$r = \frac{a 3}{4}$
For Fcc
$a 3 = 4 r$
$r = \frac{a 3}{4}$
For $N a Cl$ type solid
$r_{+} + r^{-} = \frac{a}{2}$