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  4. Which of the following relation is correct :-

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Q. Which of the following relation is correct :-

NTA AbhyasNTA Abhyas 2020

Solution:

For $BCCa\sqrt{3}=4r$
$r=\frac{a \sqrt{3}}{4}$
For Fcc
$a\sqrt{3}=4r$
$r=\frac{a \sqrt{3}}{4}$
For $NaCl$ type solid
$r_{+}+r^{-}=\frac{a}{2}$