Which of the following particles - neutron, proton, electron and deuteron has the lowest energy if all have the same de Broglie wavelength

Question

Which of the following particles - neutron, proton, electron and deuteron has the lowest energy if all have the same de Broglie wavelength (A) neutron (B) proton, (C) electron (D) deuteron

Tardigrade Admin · Accepted Answer

λ=( h / mv ) λ=( h /√2 Em ) So E α (1/ m ) Deuteron is mass of 1 proton and 1 neutron , hence its mass is maximum out of the given particles ,so its energy is the lowest.

Q. Which of the following particles - neutron, proton, electron and deuteron has the lowest energy if all have the same de Broglie wavelength

neutron

proton,

electron

deuteron

$λ = \frac{h}{m v}$
$λ = \frac{h}{2 E m}$
So $E α \frac{1}{m}$
Deuteron is mass of $1$ proton and $1$ neutron ,
hence its mass is maximum out of the given particles ,so its energy is the lowest.

Q. Which of the following particles - neutron, proton, electron and deuteron has the lowest energy if all have the same de Broglie wavelength

neutron

proton,

electron

deuteron

λ=mvh​ λ=2Em​h​ So Eαm1​ Deuteron is mass of 1 proton and 1 neutron , hence its mass is maximum out of the given particles ,so its energy is the lowest.

$λ = \frac{h}{m v}$
$λ = \frac{h}{2 E m}$
So $E α \frac{1}{m}$
Deuteron is mass of $1$ proton and $1$ neutron ,
hence its mass is maximum out of the given particles ,so its energy is the lowest.