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Q.
Which of the following particles - neutron, proton, electron and deuteron has the lowest energy if all have the same de Broglie wavelength
Dual Nature of Radiation and Matter
Solution:
$\lambda=\frac{ h }{ mv }$
$\lambda=\frac{ h }{\sqrt{2 Em }}$
So $E \alpha \frac{1}{ m }$
Deuteron is mass of $1$ proton and $1$ neutron ,
hence its mass is maximum out of the given particles ,so its energy is the lowest.